find the distance between point (-3,2) and (3,2)
give right answer please
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Answer:
(x1,y1)=(-3,2)
(x2,y2)=(3,2)
distance=√{(3-(-3))²+(2-2)²}
=√{(3+3)²+0}
=√(9)²
distance=9 units
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Answer:
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