find the distance between points (0,5) and (-5,0)
Answers
Answered by
110
Let d be required distance
d²=(x2-x1)²+(y2-y1)²
d²=5²+5²
d²=50
d=±√50
d=5√2
Answered by
65
Answer:
The answer is 5√2
Step-by-step explanation:
√(0+5)^2+ (0-5)^2
√25+25
√50
Distance=5√2
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