find the distance between points (0,6) and (-8,0)
Answers
Answer:
ANSWER
ANSWERLet the equation of the general form of the required circle be
ANSWERLet the equation of the general form of the required circle be x
ANSWERLet the equation of the general form of the required circle be x 2
ANSWERLet the equation of the general form of the required circle be x 2 +y
ANSWERLet the equation of the general form of the required circle be x 2 +y 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten as
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4)
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3)
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25Therefore, the equation of circle is (x−4)
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25Therefore, the equation of circle is (x−4) 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25Therefore, the equation of circle is (x−4) 2 +(y−3)
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25Therefore, the equation of circle is (x−4) 2 +(y−3) 2
ANSWERLet the equation of the general form of the required circle be x 2 +y 2 +x 2 +y 2 +2(−4)x+2(−2)y+0=0 that is x 2 +y 2 −8x−4y+0=0 can be rewritten asx 2 +y 2 −8x−4y+16+9=0+16+9(x−4) 2 +(y−3) 2 =25Therefore, the equation of circle is (x−4) 2 +(y−3) 2 =25.
Answer:
-10
Step-by-step explanation:
The distance between (0,6) and (-8,0) is -10.