Question

Find the distance between points.

a. A(6,0) B(14,0)

b. A(0,-5) B(0,10)

C. A(0,p) B(P,0)




Pls give correct answer I have increased points but pls give correct answer otherwise I will report it. Pls explain step to step.
Correct answer will be marked as brainlist​

Answer 1

Step-by-step explanation:

Using the distance formula,

$\sqrt{(x2 - x1) ^{2} + {(y2 - y1)}^{2} }$

$\mathfrak{ \textit{ \huge1.}}$

$\sqrt{ {(14 - 6}^{2} + {(0 - 0)}^{2} }$

$\sqrt{ {8}^{2} }$

$\sqrt{64} = 8 \: units$

$\mathfrak{ \textit{ \huge2.}}$

$\sqrt{ {(0 - 0}^{2} + {(10 - ( - 15))}^{2} }$

$\sqrt{ {(10 + 15)}^{2} }$

$\sqrt{ {(25)}^{2} }$

$\sqrt{625} = 25 \: units$

$\mathfrak{ \textit{ \huge3.}}$

$\sqrt{ {(p - 0)}^{2} + {(0 - P)}^{2} }$

$\sqrt{ {(p)}^{2} + {(P)}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:{ (a - b)}^{2}$

$\not{\sqrt{ {(p + P)}^{ \not2} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (a + b) ^{2}$

$( p + P ) \: units$