Question

find the distance between points p(2, -3) and Q(5,-7) . ​

Answer 1

GiveN:-

• P(2, -3)
• Q(5, -7)

To FinD:-

The distance between P and Q.

SolutioN:-

We know that,

$\large{\green{\underline{\boxed{\bf{Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}}}}}}$

where,

• x1, y1 are the coordinates of first point
• x2, y2 are the coordinates of second point
• x1 = 2
• x2 = 5
• y1 = -3
• y2 = -7

Putting the values,

$\large\implies{\sf{Distance=\sqrt{(5-2)^2+((-7)-(-3))^2}}}$

$\large\implies{\sf{Distance=\sqrt{(3)^2+(-7+3)^2}}}$

$\large\implies{\sf{Distance=\sqrt{(3)^2+(-4)^2}}}$

$\large\implies{\sf{Distance=\sqrt{9+16}}}$

$\large\implies{\sf{Distance=\sqrt{25}}}$

$\large\therefore\boxed{\bf{Distance=\frac{+}{-}5\:units.}}$

The distance between P(2, -3) and Q(5, -7) is 5 units.

Answer 2

Answer:

Here Your Answer.

Step by step Explanation:

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