Question

Find the distance between points. P (- 3, 4) and Q (4, 4)​

Answer 1

Answer:

PQ=7 units

Step-by-step explanation:

Given: x1=-3 x2=4

y1=4 y2=4

Now by distance formula,

PQ^2=(x2-x1)^2+(y2-y1)^2

PQ^2=(4-(-3))^2+(4-4)^2

PQ^2=(4+3)^2+(0)^2

PQ^2=(7)^2+0

PQ^2=49

PQ=7 units(taking square root on both sides)