Question

Find the distance between points. P (- 3, 4) and Q (4, 4).

a. 7 units          b. 3 units          c. 4 units           d. 1 units​

Answer 1

Answer:-

a. 7 units

step by step explanation:-

given:- X1 = -3. ,X2 = 4.

Y1 = 4. , Y2=. 4.

Now distance formula.

PQ^²= (X2 - X1)^² + (Y2-Y1)^²

PQ^²= (4-(-3))^² + (4-4)^²

PQ^²= (4+3)^² + (0)^²

PQ^²= ( 7 )^² + 0

PQ^²= 49

therefore PQ=7 ....(taking sq.root both side)

so answer is 7