Question

Find the distance between points P(-7,-4) and
Q(-2,8)​

Answer 1

Answer:

this is the right answer

Answer 2

➳Distance between points P(-7 , -4) Q (-2 , 8 )

$distance \: between \: 2 \: points \: \\ = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } \\ pq = \sqrt{( - 2 - ( - 7)) {}^{2} + (8 - ( - 4)) {}^{2} } \\ = \sqrt{( - 2 + 7) {}^{2} + (8 + 4) {}^{2} } \\ = \sqrt{5 {}^{2} + 12 {}^{2} } \\ = \sqrt{25 + 144 } \\ = \sqrt{169} \\ = 13 unit$

Distance of points P(-7, -4) & Q(-2, -8) is 13 unit