Question

Find the distance between points P(-7;-4) Q(-2;8)

Answer 1

Answer:

p(-7,-4) q(-2,8)

$d = \sqrt{}(x2 - x1) {}^{2} + (y2 - y1) {}^{2}$

Step-by-step explanation:

PQ =

$pq = \sqrt{ ( - 2 - 7) { }^{2} } + (8 + 4) \\ = \sqrt{(9) {}^{2} } + (12) {}^{2} \\ = \sqrt{81 + 144} \\ = \sqrt{225} \\ = \sqrt{15 \times 15} \\ = \sqrt{15 \: \: \:units}$