find the distance between (t1²,2t²)&(t2²,2t2) if t1 & t2 are the roots of x²-2√3+2
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Bhai ye pura likhna hai
Given equation
x
2
−2
2
x+1=0
t
1
+t
2
=−
1
−2
2
=2
2
t
1
t
2
=1
distance between the points
(t
1
3
+t
2
3
)
2
+(
2
t
1
+
2
t
2
)
2
=
((t
1
+t
2
)(t
1
2
−t
1
t
2
+t
2
2
))
2
+2(t
1
+t
2
)
2
=
((t
1
+t
2
)((t
1
+t
2
)
2
−3t
1
t
2
))
2
+2(t
1
+t
2
)
2
=
((2
2
)((2
2
)
2
−3))
2
+2(2
2
)
2
=
200+16
=
216
=6
6
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