Question

find the distance between the 6, 2 and 4, 4​

Answer 1

Answer:

6-2=4

4-4=0

as we have subtract both of the pairs of digits

Answer 2

The distance between the points (6, 2) and (4, 4​) is equal to 2$\sqrt{2}$ units.

Step-by-step explanation:

Here, $x_{1} =6,y_{1} =2$ and $x_{2} =4,y_{2} =4$

To find, the distance between the points (6, 2) and (4, 4​) = ?

We know that,

The distance between the two points

= $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(4-6)^2+(4-2)^2}$

= $\sqrt{(-2)^2+(2)^2}$

= $\sqrt{4+4}$

= $\sqrt{8}$

= 2$\sqrt{2}$ units

∴ The distance between the points (6, 2) and (4, 4​) = 2$\sqrt{2}$ units

Thus, the distance between the points (6, 2) and (4, 4​) is equal to 2$\sqrt{2}$ units.