Question

find the distance between the co ordinates of the points a 2,3 and b, 10,-3​

Answer 1

Answer:

Distance formula,

\begin{gathered} = \sqrt{(x _{2} - x _{1})^{2} + (y _{2} - y _{1})^{2} } \\ = \sqrt{(10 - 2)^{2} + ( - 3 - 3)^{2} } \\ = \sqrt{(8)^{2} + ( - 6)^{2} } \\ \end{gathered}

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

=

(10−2)

2

+(−3−3)

2

=

(8)

2

+(−6)

2

\begin{gathered} = \sqrt{64 + 36 } \\ = \sqrt{100} \\ = 10\end{gathered}

=

64+36

=

100

=10

Answer 2

Step-by-step explanation:

√((y"-y')^2+(x"-x')^2)

y'=3,y"=-3

x'=2,x"=10

√((3-(-3))^2+(10-2)^2)

√(6^2+8^2)

√(36+64)=√100=10