Find the distance between the directrix of the ellipse x^2/36 +(y^2/20) = 1
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Toolbox:.
Distance between the directrices is a/e
Eccentricity =√a2−b2/a
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Answer : 99
Given equation of the ellipse is x^2/36+y^2/20 = 1
∴a^2=36
⇒a=±6
b^2=20
⇒b=±2√5
∴e=√a^2−b^2/a
e=√36−20/6
=4/6
=2/3
Hence the distance between the directrices is a/e
→6/2/3 = 9
PLS MARK AS BRIANLIEST
Toolbox:.
Distance between the directrices is a/e
Eccentricity =√a2−b2/a
———————————————————
Answer : 99
Given equation of the ellipse is x^2/36+y^2/20 = 1
∴a^2=36
⇒a=±6
b^2=20
⇒b=±2√5
∴e=√a^2−b^2/a
e=√36−20/6
=4/6
=2/3
Hence the distance between the directrices is a/e
→6/2/3 = 9
PLS MARK AS BRIANLIEST
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