find the distance between the following pair of points (a sin a, -bcos a) And (-a cos a, b sin a)
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distance= √(x²-x¹)²+(y²-y¹)²
=√(-acosa-asina)²+(bsina+bcosa)²
=√a²cos²a+a²sin²a+2a²sinacosa+b²sin²a +b²cos²a+2b²sinacosa
=√a²+2a²sinacosa +b²+2b²sinacosa
=√a²(1+2sinacosa)+b²(1+sinacosa)
=√(a²+b²)(1+2sinacosa)
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=√(-acosa-asina)²+(bsina+bcosa)²
=√a²cos²a+a²sin²a+2a²sinacosa+b²sin²a +b²cos²a+2b²sinacosa
=√a²+2a²sinacosa +b²+2b²sinacosa
=√a²(1+2sinacosa)+b²(1+sinacosa)
=√(a²+b²)(1+2sinacosa)
PLEASE SELECT MY ANSWERS AS BRAINLIEST
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