Math, asked by md0332099, 2 months ago

find the distance between the following pairs of points 1.(-5, 7) and (-1, 3)​

Answers

Answered by moonchild138
2

Step-by-step explanation:

Here is answer. Hope it helps. =)

Have a gala day.

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Answered by Anonymous
22

Answer :-

Step by step explanation:-

Question :-

find the distance between the following pairs of points

.(-5, 7) and (-1, 3)

Formula Implemented:-

\sf\sqrt{x_1-x_2)^2 + (y_1-y_2)^2}

Solution:-

(-5, 7) and (-1, 3)

Where

x1 = -5

x2 = -1

y1 = 7

y2 = 3

Substitute in formula We get diatance between the points

\sf\sqrt{x_1-x_2)^2 + (y_1-y_2)^2}

\sf\sqrt{(-5-[-1])^2 + ( 7 -3 )^2 }

\sf\sqrt{(-5+1)^2 + (4)^2}

\sf\sqrt{(-4)^2 + 16}

\sf\sqrt{16+ 16}

\sf\sqrt{32} units

\sf\sqrt{(4)(8)}

\sf\sqrt{4} \sf\sqrt{8}

2 \sf\sqrt{8} units

2 ×2 \sf\sqrt{2}

4 \sf\sqrt{2}

So, diatance between .(-5, 7) and (-1, 3) is 4 \sf\sqrt{2}

Know more :-

Mid point formula

\sf\dfrac{x1+x2+x3}{3}, \sf\dfrac{y1+y2+y3}{3}

Incentre formula

\sf\dfrac{ax1+bx2+cx3}{a+b+c}, \sf\dfrac{ay1+by2+cy3}{a+b+c}

Section formula for Internal division

\sf\dfrac{mx2 + nx1}{m+n},\sf\dfrac{my2+ny1}{m+n}

Section formula for external division

\sf\dfrac{mx2 -nx1}{m-n},\sf\dfrac{my2-ny1}{m-n}

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