Question

find the distance between the following pairs of points (√3+1,1)and(0,√3)

Answer 1

Use distant formula. The distance between 2 points on a plane is given by X=$\sqrt{(x2-x1)^2}$ Y=$\sqrt{(y2-y1)^2}$ So we have x2=√3+1                      x1=0  ( x2 and x1 can have vice versa values also as the negative will get canceled by square) And let Y2=1              Y3=√3 Distance is  $\sqrt{X-Y}$ So we get , after substituting and squaring , the value as √8.

Answer 2

Answer:

follow

Step-by-step explanation:

Use distant formula. The distance between 2 points on a plane is given by X=\sqrt{(x2-x1)^2}

(x2−x1)

2

Y=\sqrt{(y2-y1)^2}

(y2−y1)

2

So we have x2=√3+1 x1=0 ( x2 and x1 can have vice versa values also as the negative will get canceled by square) And let Y2=1 Y3=√3 Distance is \sqrt{X-Y}

X−Y

So we get , after substituting and squaring , the value as √8.