Find the distance between the following pairs of points (-8/5,-2) and (2/3,2)
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Answer:4.59 sq units
Step-by-step explanation:let the two points be p and q
Let x2=2/3 and x1= -8/5
Let y2=2 and x1= -2
By distance formulae
Pq=over root (x2-x1)^2 + (y2-y1)^2
Pq=over root (2/3--8/5)^2 + (2--2)^2
Pq=over root (34/15)^2 + (4)^2
Pq=over root (5.10+16)
Pq=over root 21.10
Pq=4.59 sq units
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