find the distance between the following points
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given points are
[1/2 , 3/2] and [3/2,-1/2]
let x1 y2 x2 y2
now ,
√(x2-x1)² +)(y2-y1)²
√(3/2 -1/2)² +(-1/2-3/2)²
√(2/2)² + (-4/2)²
√1+4
√5
[1/2 , 3/2] and [3/2,-1/2]
let x1 y2 x2 y2
now ,
√(x2-x1)² +)(y2-y1)²
√(3/2 -1/2)² +(-1/2-3/2)²
√(2/2)² + (-4/2)²
√1+4
√5
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