Find the distance between the following points
(i) A = (2, 0) and B(0, 4)
(ii) P(0, 5) and Q(12, 0)
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Answered by
4
Hi ,
****************************************
We know that ,
The distance between the two points
A( x1 , y1 ) , B( x2 , y2 ) is
AB = √ ( x2 - x1 )² + ( y2 - y1 )²
******************************************
Now ,
1 ) A( 2 , 0 ) = ( x1 , y1 )
B ( 0 , 4 ) = ( x2 , y2 )
AB = √ ( x2 - x1 )² + ( y2 - y1 )²
= √ ( 0 - 2 )² + ( 4 - 0 )²
= √ ( -2 )² + 4²
= √ 4 + 16
= √ 20
= √ ( 2 × 2 ) × 5
AB = 2√5
2 ) P( 0 , 5 ) = ( x1 , y1 ),
Q( 12 , 0 ) = ( x2 , y2 )
PQ = √ ( 12 - 0 )² + ( 0 - 5 )²
= √ 12² + 5²
= √ 144 + 25
= √ 169
PQ = √ 13 × 13
PQ = 13
I hope this helps you.
: )
****************************************
We know that ,
The distance between the two points
A( x1 , y1 ) , B( x2 , y2 ) is
AB = √ ( x2 - x1 )² + ( y2 - y1 )²
******************************************
Now ,
1 ) A( 2 , 0 ) = ( x1 , y1 )
B ( 0 , 4 ) = ( x2 , y2 )
AB = √ ( x2 - x1 )² + ( y2 - y1 )²
= √ ( 0 - 2 )² + ( 4 - 0 )²
= √ ( -2 )² + 4²
= √ 4 + 16
= √ 20
= √ ( 2 × 2 ) × 5
AB = 2√5
2 ) P( 0 , 5 ) = ( x1 , y1 ),
Q( 12 , 0 ) = ( x2 , y2 )
PQ = √ ( 12 - 0 )² + ( 0 - 5 )²
= √ 12² + 5²
= √ 144 + 25
= √ 169
PQ = √ 13 × 13
PQ = 13
I hope this helps you.
: )
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5
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