find the distance between the foot of the ladder to foot of the water tank which is at height 8mtr
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Let AC be the ladder, AB be the wall.
Then in △ABC,
AC2=AB2+BC2 (Pythagoras theorem)
102=82+BC2
BC2=62
BC=6 m
Hence, the foot of the ladder is 6 m from the wall.
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Step-by-step explanation:
above ⬆⬆⬆⬆ is the answer..
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