Question

Find the distance between the lines 3x 2y=5 and 6x 4y=6

Answer 1

Answer:

Distance between two given lines

$\frac{2}{ \sqrt{13} } \: \: \: units$

Step by step Explanation:

To find the distance between the lines

3x+2y- 5=0 and 6x+4y=6 or 3x+2y-3=0

We know that distance between two parallel lines

$ax + by + c_1 = 0 \\ ax + by + c_2 = 0$

distance between these lines

$\boxed{d = \bigg| \frac{c_2 - c_1}{ \sqrt{ {a}^{2} + {b}^{2} } } \bigg|}$

So,

$d = \bigg| \frac{ - 3 + 5 }{ \sqrt{ {3}^{2} + {2}^{2} } } \bigg| \\ \\ d = | \frac{2}{ \sqrt{13} } |$

Hope it helps you.

Answer 2

we know that distance

Step-by-step explanation:

Hope it helps