Question

Find the distance between the lines 3x+4y+5=0 and 6x+8y=25

Options
a. 0
b. 2/3
c. 3/2
d. 4/3

Answer 1

write international words of 61892790

Answer 2

Given,

Equation of two lines 3x+4y+5=0 and 6x+8y=25.

To find,

The distance between the lines.

Solution,

• The distance between the two lines can be founded by (c2-c1)/(√a²+b²), where ax+by+c1=0 and ax+by+c2=0 are equations of two lines.

3x+4y+5 = 0 and 6x + 8y=25 are straight lines.

6x+8y-25=0 can be reduced to 3x+4y-25/2=0.

Now, putting the values in the formula-

⇒ mod((-25/2-5)/√(3)²+(4)²)

⇒ mod(-35/2/√25)

⇒ mod(-35/2)/5

⇒ mod(-35/10)

⇒ mod(-7/2) = 7/2

Hence, the distance between the two lines 3x+4y+5=0 and 6x+8y=25 are 7/2.