find the distance between the lines 3x+4y+6=0 and 6x+8y-11=0
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Step-by-step explanation:
3x+4y=9,6x+8y+15=0
As can be seen from the slopes of the given lines, these two lines are parallel.
They can be written as 3x+4y=9 and 3x+4y=
2
−15
Therefore, the perpendicular distance between these lines is obtained by =
A
2
+B
2
C
1
−C
2
=
9+16
9+
2
15
=
5
2
33
=
10
33
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