Find the distance between the pairs of points (2a, 6b), (–3 a, –2 b)
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Step-by-step explanation:
Given :-
The pairs of points (2a, 6b), (–3 a, –2 b)
To find:-
Find the distance between the pairs of points (2a, 6b), (–3 a, –2 b) ?
Solution:-
Given points are (2a, 6b), (–3 a, –2 b)
Let(x1, y1)=(2a, 6b)=>x1=2a and y1=6b
Let (x1, y1)=(–3 a, –2 b)=>x2=-3a and y2=-2b
We know that
The distance between two points (x1, y1) and
(x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units
Distance between given two points
=> √[(-3a-2a)^2+(-2b-6a)^2] units
=>√[(-5a)^2+(-8a)^2] units
=> √(25a^2+64b^2) units
Answer:-
The distance between given two points is
√(25a^2+64b^2) units
Used formulae:-
- The distance between two points (x1, y1) and (x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units
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