Math, asked by kanishkas0805, 16 hours ago

Find the distance between the pairs of points (2a, 6b), (–3 a, –2 b)​

Answers

Answered by tennetiraj86
3

Step-by-step explanation:

Given :-

The pairs of points (2a, 6b), (–3 a, –2 b)

To find:-

Find the distance between the pairs of points (2a, 6b), (–3 a, –2 b) ?

Solution:-

Given points are (2a, 6b), (–3 a, –2 b)

Let(x1, y1)=(2a, 6b)=>x1=2a and y1=6b

Let (x1, y1)=(–3 a, –2 b)=>x2=-3a and y2=-2b

We know that

The distance between two points (x1, y1) and

(x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units

Distance between given two points

=> √[(-3a-2a)^2+(-2b-6a)^2] units

=>√[(-5a)^2+(-8a)^2] units

=> √(25a^2+64b^2) units

Answer:-

The distance between given two points is

√(25a^2+64b^2) units

Used formulae:-

  • The distance between two points (x1, y1) and (x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units
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