Question

Find the distance between the parallel lines 3x-4y+7=0 and 3x-4y+5=0

Answer 1

Given
parallel lines
3x -4y+7=0
perp length from origin
P1= 7/√(3)sq +(-4)sq
=7/5

and another line
3x-4y+5=0
P2= 5/√(3)sq+(-4)sq
=5/5

Now distance b/w parallel lines
D=P1-P2
=7/5-5/5
=2/5 units Ans