Question

find the distance between the parallel lines p(x+y)+q=0 and p(x+y)-r=0

Answer 1

➡HERE IS YOUR ANSWER⬇

The lines are given by :

px + py = -q .....(i)
px + py = r .....(ii)

These lines are parallel lines.

Then, the distance between the two lines

$= \frac{( r + q)}{ \sqrt{ {p}^{2} + {p}^{2} } } \: units$

⬆HOPE THIS HELPS YOU⬅