Question

Find the distance between the parallel planes, 2x + y + 2z – 8 = 0 and 4x + 2y + 4z + 5 = 0

Answer 1

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SOLOTION:--

Given planes are2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0

multiplying 1stequation by 2 we get

4x+2y+4z=16 and 4x+2y+4z=-5

distance between the planes=16-(-5)/sqrt(42+22+42)

=21/6=7/2