Find the distance between the parallel planes ax+by+cz+d1=0 and ax+by+cz+d2=0
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Answer:
Step-by-step explanation:
distance d = |d2 - d1|/ {a^2+b^2+c^2}^1/2
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1
Step-by-step explanation:
3i , then 3x+2y is equal to: a -20, b -60, c -120, d 60
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