Question

find the distance between the parallel sides of length 25 metre and 36 metre of the trapezium area is 366 metre square​

Answer 1

area of trapezium = 366m²

1/2×(sum of// sides) ×height =366m²

1/2 ×(25+36)×h = 366m²

1/2×61×h =366m²

61×h = 366 ×2

h = 366×2/61

h=12m

Answer 2

Given:-

• Length of sides of trapezium is 25 metres and 36 metres.
• Area of trapezium is 366² metres.

To Find:-

• Distance between their sides?

Solution:-

Area of trapezium

$\dag{ \underline{ \boxed{ \rm { \pink{½ \times (a + b) \times h}}}}}$

Where,

• a and b = sides
• h = height

According to the question

$\rm→ 366 = ½ \times (25 + 36) \times h \\ \\ \rm→ 366 = ½ \times (61 ) \times h \\ \\ \rm→ 366 = 30.5 \times h \\ \\ \rm→ \frac{366}{30.5} = h \\ \\ \rm→ 12 = h$

Hence, the difference between their lengths is 12 cm.