Question

find the distance between the parallel sides of length 25m and 36m of the trapezium whose area is 366m²​

Answer 1

Answer:

• Distance between parallel sides is 12 m.

Step-by-step explanation:

Given :-

• Length of parallel sides are 25 m and 36 m.
• Area of trapezium is 366 m².

To find :-

• Distance between the parallel sides.

Solution :-

Let, Distance between parallel sides be x m.

We know,

Area of trapezium = (a + b)/2 × h

Where,

• a and b are parallel sides.
• h is height or we can say distance between parallel sides of trapezium.

Put all values in formula:

⇒366 = (a + b)/2 × h

⇒366 = (25 + 36)/2 × x

⇒366 = 61/2 × x

⇒366 × 2 = 61 × x

⇒732 = 61 × x

⇒732/61 = x

⇒x = 12

We take,

Distance between parallel sides be x.

Thus,

Distance between parallel sides is 12 m.

Answer 2

Answer:

Given :-

• The parallel sides of length 25 m and 36 m of the trapezium whose area is 366 m².

To Find :-

• What is the distance between the parallel sides.

Formula Used :-

★ Area of trapezium = ½ × sum of parallel sides × Height ★

Solution :-

Let, the height or distance between the parallel sides be x

Given :-

• Area of trapezium = 366 cm²
• Sum of parallel sides = 25 m + 36 m

According to the question by using the formula we get,

⇒ 366 = ½ × 25 + 36 × x

⇒ 366 = ½ × 61 × x

⇒ 366 × 2 = 61 × x

⇒ 732 = 61 × x

⇒ 732 ÷ 61 × x

⇒ 12 = x

➠ x = 12 m

∴ The distance between the parallel sides is 12 m .

Let's Verify :-

↦ 366 = ½ × 25 + 36 × h

Put x = 12 we get,

↦ 366 = ½ × 25 + 36 × 12

↦ 366 = ½ × 61 × 12

↦ 366 = ½ × 732

↦ 366 = 366

➦ LHS = RHS

Hence, Verified ✔