Question

Find the distance between The parellal line 3x+2y=5, 6x+2y=6

Answer 1

Answer:

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Answer 2

Answer:

3x+4y=9⟹4y=−3x+9⟹y=−34x+943x+4y=9⟹4y=−3x+9⟹y=−34x+94

6x+8y=15⟹8y=−6x+15⟹y=−68x+1586x+8y=15⟹8y=−6x+15⟹y=−68x+158

⟹y=−34x+158⟹y=−34x+158

slopemofthelines=−34slopemofthelines=−34

Hence both lines are parallel Hence both lines are parallel

Y intercept of the first line =94Y intercept of the first line =94

Y intercept of the second line =158Y intercept of the second line =158

Difference between the y- intercepts=∣∣∣94−158∣∣∣Difference between the y- intercepts=|94−158|

=∣∣∣188−158∣∣∣=|188−158|

=38=38

1+m2−−−−−−√=1+916−−−−−−√=2516−−−√=541+m2=1+916=2516=54

Distance between the lines =38÷54=38×45=310Distance between the lines =38÷54=38×45=310