Question

Find the distance between the planes 2x – y + 2z = 5 and 5x – 2·5y + 5z = 20.

Answer 1

Hey !!

Answer:

1 unit

Step-by-step explanation:

P₁ = 2x - y + 2x = 5

P₂ = ₂x - 2.5y + 5z = 20

        => 2x - y + 2z = 20 / 2.5

= 20 / 5 × 2

= 8

Distance = | d₂ - d₁ / √a² + b² + c² |

    = | 8 - 5 / √(2)² + (-1)² + (2)² |

     = | 3 / √4 + 1 + 4 |

     = | 3 / √9 |

     = 3 / 3

      = 1 unit.

Good day !!