Question

Find the distance between the point (-2,3)&(3,15)

Answer 1

formula of distance :

√(x2-x1)^2+(y2-y1)^2

(-2,3)=X1,y1

(3,15)=X2,y2

substitute

=√(3-(-2))^2+(15-3)^2

=√(5)^2+(12)^2

=√25+144

=√169

=13

Therefore the distance is 13.

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Answer 2

Answer:

13

Step-by-step explanation:

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