Question

find the distance between the point (3,1) and (6,4)​

Answer 1

let,

x1 = 3, y1 = 1

x2 = 6, y2 = 4

Therefore,

By distance formula,

$\sqrt{({x2 - x1 } )^{2} + ({y2 - y1)^{2} }} \\ = \sqrt{ {(6 - 3)}^{2} + {(4 - 1)}^{2} } \\ = \sqrt{ {3}^{2} + {3}^{2} } \\ = \sqrt{9 + 9 } \\ = \sqrt{18} \\ = \sqrt{9 \times 2 } \\ = 3 \sqrt{2}$

Therefore, distance between the point (3,1) and (6,4) is 3sqrt{2} units

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