Find the distance between the point (-3, 4, -6) and its image in the XY-plane
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Answer:
12 units
Step-by-step explanation:
the given point is in VI octant ( -,+,-)
the image in XY plane in II octannt (-,+,+)
hence... the distance = 2 × z-cordinate
i,e,...|2 × 6| = 12 units
Note :
can use distance formule for (-3, 4, -6) & (-3, 4, +6)
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