Question

Find the distance between the point (3, 4) and (8,-6).

Answer 1

Distance between two points is √(x2-x1)^2+(y2-y1)^2

=✓(8-3)^2+(-6-4)^2

=✓25+100

=✓125

Answer 2

The distance between the point (3, 4) and (8,-6) is $5\sqrt{5}$ unit.

Step-by-step explanation:

To find : The distance between the point (3, 4) and (8,-6) ?

Solution :

The distance between two point is given by,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, the points are $(x_1,y_1)=(3,4)$and $(x_2,y_2)=(8,-6)$

Substitute the values,

$d=\sqrt{(8-3)^2+(-6-4)^2}$

$d=\sqrt{(5)^2+(-10)^2}$

$d=\sqrt{25+100}$

$d=\sqrt{125}$

$d=5\sqrt{5}$

Therefore, the distance between the point (3, 4) and (8,-6) is $5\sqrt{5}$ unit.

#Learn more

Distance between the points (-2,1) and (2,4) is units

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