Question

find the distance between the point (-8/2,2) and (2/5,2)​

Answer 1

$\textbf{Formula used:}$

$\text{The distance between two points }[tex][tex](x_1,y_1)\:\text{and}\:(x_2,y_2)$$\text{is}$

$\bf\;d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$\text{Given points are (-8/2,2) and (2/5,2) }$

$\text{That is, (-4,2) and (2/5,2)}$

$\text{The distance between the given points is}$

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$d=\sqrt{(-4-\frac{2}{5})^2+(2-2)^2}$

$d=\sqrt{(\frac{-22}{5})^2+(0)^2}$

$d=\sqrt{\frac{484}{25}}$

$d=\frac{22}{5}$

$d=4.4\;\text{units}$

$\therefore\textbf{The distance between the given points is 4.4 units}$

Answer 2

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