Question

Find the distance between the point A(4,5)and B(-2,1)​

Answer 1

Answer:

$2 \sqrt{13}$

Step-by-step explanation:

$(4 \: \: , \: 5) \\ \\ ( - 2 \: \: , \: 1) \\ \\ distance \: = \: \sqrt{ {(4 - ( - 2))}^{2} + {(5 - 1)}^{2} } \\ \\ = \sqrt{ {6}^{2} + {4}^{2} } \\ \\ = \sqrt{36 + 16} \\ \\ = \sqrt{52} \\ \\ \sqrt{4 \times 13} \\ \\ = \sqrt{4} \sqrt{13} \\ \\ = 2 \sqrt{13} \\ \\ distance = 2 \sqrt{13}$

$formula \\ \\ distance \: \: between \: (x1,y1) \: \: and \: \: (x2,y2) \: is \: given \: \: by \\ \\ d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

Hope it Helps

Answer 2

Yo!

Here's the answer!

To find: the distance b/w point A(4,5) and B(-2,1)

Solution:

To find the distance between 2 particular points,we use the DISTANCE FORMULA which is: √(x2-x1)²+(y2-y1)²

So,

X1= 4

X2= -2

Y1= 5

Y2= 1

Therefore,

√(-2-4)²+(1-5)²

= √(-6)²+(-4)²

=√36+16

=√52.

Upon simplyfing further we get:

√13×2×2

=2√13 is the distance b/w the 2 points. Hope it helps!

–TGA.