find the distance between the point A(x,1/x) and B(x,1/x), please dont spam ,answer correctly for brainliest+5 thanks + 50 points
Answers
Answered by
3
Answer:
AB² = (x1 - x2)² + (y1 - y2)²
(5)² = ( 1 - x )² + ( 1 - 1 )²
25 = 1 - 2x + x²
x² - 2x - 24 = 0
x² - (6 - 4 )x - 24 = 0
x² - 6x + 4x - 24 = 0
x (x - 6) + 4 (x - 6) = 0
(x + 4) (x - 6) = 0
Therefore x = -4 or x = 6
Distance can't be negative.
So x = 6
Answered by
1
Answer:
P=(x ,y 1 )=(x,−1)
Q=(x
2 ,y 2 )=(3,2)
25=(3−x)
2 +(2+1) 2
25=(9+x 2 −6x+9)
x 2 −6x−7=0
x 2 −7x+x−7=0
x(x−7)+1(x−7)=0
x=−1,7
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