Question

find the distance between the point is A(P,-3) and B(10,-9)
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Answer 1

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Distance between 2 points = √[ (y₂ - y₁)² + (x₂ - x₁)² ]

In the given case,

x₁ = P                        y₁ = -3

x₂ = 10                      y₂ = -9

Hence,

Distance = √ [ (-9 - -3)² + (10 - P)² ]

                = √ [ (3 - 9)² + 10² + P² - 20P ]

                = √ [6² + 100 + P² - 20P]

                = √ [36 + 100 + P² - 20P]

                = √ [136 + P² - 20P]

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Answer 2

Step-by-step explanation:

use distance formula.....

$\sqrt{{(10 - p)}^{2} +{ ( - 9 - - 3)}^{2} }$

$\sqrt{100 + {p}^{2} - 20p + 36}$

$\sqrt{ {p}^{2} - 20p + 136}$

$\sqrt{20 + - \sqrt{400 - 4 \times 136} }$

$this \: gives \: imaginary \: roots \:$

$thus \: no \: solution$