find the distance between the point - P(a+b,a-b) and Q(a-b,a+b)
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Answer:
2b²
Step-by-step explanation:
Distance formula²=(x2-x1)²+(y2-y1)²
where x1=a+b, y1=a-b x2=a-b and y2=a+b
PQ²=[(a-b-a+b)²+{a+b-(a-b)}]
={0+(a+b-a+b)²}
=(2b)²
=4b²
PQ=2b²
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