Question

find the distance between the pointa p ( -1 , 1 ) and q ( 5 , -7 )​

Answer 1

Answer:

distance between the point p(-1,1) and q(5, -7) is 10.

Step-by-step explanation:

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } \\ d = \sqrt{ ({5 - ( - 1))}^{2} + {( - 7 - 1)}^{2} } \\ d = \sqrt{ {6}^{2} + ( { - 8})^{2} } \\ d = \sqrt{36 + 64} \\ d = \sqrt{100} \\ d = 10$

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