Question

Find the distance between the points (10,8) and (3,3)​

Answer 1

Answer:

a(10,8)

b(3,3)

$ab = \sqrt{(3 - 10) {}^{2} + (3 - 8) {}^{2} }$

$ab = \sqrt{( - 7) {}^{2} + ( - 5) {}^{2} }$

$ab = \sqrt{49 + 25}$

$ab = \sqrt{74}$

Answer 2

✬ The distance between the points (10,8) and (3,3) is √74 units.✬

Step-by-step explanation:

Given: The distance between the points (10,8) and (3,3).

To find: Distance between the points

Required Formula:

• Distance between the points = √(x₂ - x₁)² + (y₂ - y₁)²

Let the points be P(x1,y1) = (10,8) and Q(x2,y2) = (3,3).

Let's do it,

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Putting the values,

$\\ :\implies\sf{PQ = \sqrt{{(3-10)}^{2}+{(3-8)}^{2}}} \\ \\ :\implies\sf{PQ = \sqrt{ {( - 7)}^{2} + {( - 5)}^{2} } } \\ \\ :\implies\sf{PQ = \sqrt{49 + 25} } \\ \\ :\implies \underline{ \boxed{\frak{PQ = \sqrt{74} \: units}}} \: \pink{ \bigstar}$

• Hence,The distance between the points is √74 units.