Question

find the distance between the points (2,-2)AND (14,10)
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Answer 1

Answer:

The ans is approximately 16.97 sq. units.

Please refer to attachment.

Hope it Helps!!!

Answer 2

Answer:12$\sqrt{2}$ sq units

Step-by-step explanation:

distance = $\sqrt{} (x2-x1)+(y2-y1)$

= $\sqrt{(14-2)^{2} +(10+2)^{2} }$

$\sqrt{12^{2} +12^{2} }$

$\sqrt{ 144+144}$

$\sqrt{288 }$

=$12\sqrt{2}$