Question

find the distance between the
points (2,-3) and (1,1)​

Answer 1

Answer:

√17

Step-by-step explanation:

√{1-2}²+{1-(-3)}²

√(-1)²+(1+4)²

√1+16

√17

hope this answer may help you....

Answer 2

Step-by-step explanation:

Refer figure for better understanding

As per Pythagoras theorem

${hypotenuse}^{2} = {base}^{2} + {altitude}^{2} \\ in \: a \: right \: angled \: triangle$

So,

${(ac)}^{2} = {(ab)}^{2} + {(bc)}^{2} \\ {(ac)}^{2} = {4}^{2} + {1}^{2} \\ {(ac)}^{2} = 16 + 1 = 17$

Hence

$(ac) = \sqrt{17} = 4.123$

Distance between points (1,1) and (2,-3) is 4.123