find the distance between the points (2,-3) and (14,10)
Answers
Answered by
1
d=√(14-2)² + (10--3)²
= √12² + 13²
= √144+169
= √313units
This will help you.
Mark brainliest if helpful.....
Answered by
2
hey! your answer↓
x1=2 , y1=-3
x2=14 , y2=10
distance between these points=
√(x2-x1) ^2+(y2-y1) ^2
=√(14-2) ^2+[10-(-3) ]^2
=√12^2+13^2
=√144+169
=√313
=17.69
hope that it will help you
ashish309988:
hlo
no thank u a lot gggggggggg
i have a doubt how to 17.69
i know 313 has no route but i dont know how to get the ans
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