Question

find the distance between the points (2,-5) and (-2,3)

Answer 1

Answer:

Step-by-step explanation:

• d=√((x_2-x_1)²+(y_2-y_1)²)
• (2 is x1 -5 is x2)
• (-2is y1  3 is y2 try to do this

Answer 2

${\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}}$

Given

⠀⠀⠀⠀• Points are (2,-5) and (-2,3)⠀⠀⠀

To Calculate

⠀⠀⠀⠀ • Distance __?⠀⠀⠀

Step by step explanation

⠀⠀⠀⠀⠀

⠀⠀⠀ ☆ Using formula ☆

⠀⠀⠀⠀⠀

$AB = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

⠀⠀⠀⠀⠀

The Given points are A(2,-5) and B(-2,3)

Then

x1 = 2

y1 = -5

x2 = -2

y2 = 3

$AB = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

Putting values,

$⠀⠀⠀⠀⠀➙ \: \sqrt{( - 2 - 2) {}^{2} + (3 - ( - 5)) {}^{2} }$

$⠀⠀⠀⠀⠀➙ \: \sqrt{( - 4) {}^{2} + (3 + 5) {}^{2} }$

$⠀⠀⠀⠀⠀➙ \: \sqrt{16 + 64}$

$⠀⠀⠀⠀⠀➙ \sqrt{80}$

$⠀⠀⠀⠀⠀➙ \sqrt{16 \times 5}$

$⠀⠀⠀⠀⠀➙ \: 4 \sqrt{5} \: \: units$

${\huge{\underline{\underline{\sf{\blue{Hence :-}}}}}}$

⠀⠀⠀⠀• Distance ➫ 4√5 units

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⠀⠀⠀⠀⠀☆ Additional information ☆

1) The distance of the point P(x,y) from the origin ⠀O(0,0) is Given by

⠀⠀⠀⠀⠀➙ OP = √x²+y²

2) Any point on the x-axis is of the form (x,0)

3) Any point on the y-axis is of the form (0,y)

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