Question

Find the distance between the points (√2,-7√3 ) and (4√2,8√3 )

Answer 1

Step-by-step explanation:

Given as :

The points are x_1x

1

, y_1y

1

= 7 , 8

And x_2x

2

, y_2y

2

= - 2 , 3

Let The distance between these points = D unit

∵ Distance = \sqrt{(x_1 - x_2)^{2} + (y_1-y_2)^{2} }

(x

1

−x

2

)

2

+(y

1

−y

2

)

2

Or, D = \sqrt{(7 + 2)^{2} + (8 - 3)^{2} }

(7+2)

2

+(8−3)

2

Or, D = \sqrt{9^{2}+5^{2} }

9

2

+5

2

Or, D = \sqrt{106}

106

unit

Or The distance between these points = D = \sqrt{106}

106

unit