Find the distance between the points (3,-2) and (15,3)
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Answer:
13 units
Step-by-step explanation:
D = √ [(x2 − x1)^2 + (y2 − y1)^2]
D = √ [(15 − 3)^2 + (3 − (-2))^2]
D= √ [(12)^2+(5)^2]
D= √ (144+25)
D= √ (169)
D=13
Therefore, Distance =13units
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