find the distance between the points (3,4,-2) and (1,0,7)?
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Answer:
√101
Step-by-step explanation:
The distance between the points (x1 ,y1 ,z1) and (x2, y2, z2) is √[(x1 −x2)² + (y1 - y2)² + (z1-z2)²]
So the distance between (3,4,−2) and (1,0,7) is
√[(3−1)² +(4−0)² +(−2−7)²]
= √[2² +4² +9²]
= √[4+16+81]
= √101
jayanthboggala123:
thanks
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